Futuremedstudent? Posted August 27, 2008 Report Share Posted August 27, 2008 Hello, As a side not, I hate organic chemistry. It was my worst mark at university and trying to learn it for the MCAT is making me very sad. Can somebody explain to me what exactly are pi electrons, and how to determine aromaticity by this huckel number? I'm just not getting it by reading this 2nd hand TPR book. Link to comment Share on other sites More sharing options...
heart Posted August 28, 2008 Report Share Posted August 28, 2008 If I remember correctly, pi electrons are the one further away from the nuclei; they're more reactive/unstable. Pi bonds are weaker than sigma bonds, but each double bond (pi bond + sigma bond) is stronger than a single bond (sigma bond alone). Again if I remember correctly, Huckel's rule states that for a cyclic molecule to be aromatic/resonant it must have 4n+2 pi electrons. Think of benzene, it has partial double bonds (6 sigma bonds + 3 pi bonds); when you draw a benzene, you draw 3 double bonds. To make 3 pi bonds, you need 6 pi electrons. Hope this helps. Link to comment Share on other sites More sharing options...
dan0105 Posted August 28, 2008 Report Share Posted August 28, 2008 http://mymcat.com/wiki/Aromaticity_Introduction this has been discussed before in other threads, look for aromaticity using the thread search Link to comment Share on other sites More sharing options...
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