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Holy shit that email could be a suspense novel. IP passed, whew.

 

I guess this (19th percentile cut-off, I think ~160 IP interviewed) means there are somewhere around 130 candidates going forward, for min. 75 seats?

 

Edit: Oops just re-read the email, 155 IP= 125 going forward. I can do the maths real good pls accept me.

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Holy shit that email could be a suspense novel. IP passed, whew.

 

I guess this (19th percentile cut-off, I think ~160 IP interviewed) means there are somewhere around 130 candidates going forward, for min. 75 seats?

 

Edit: Oops just re-read the email, 155 IP= 125 going forward. I can do the maths real good pls accept me.

How did you come up with 125?

How can you estimate this without having the interview score distribution, mean or SD ?

 

Or did you just take the percentage? 0.19 * 155 (using total number of IP interviewed)

 

I DOUBT if your estimation is accurate......

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How did you come up with 125?

How can you estimate this without having the interview score distribution, mean or SD ?

 

Or did you just take the percentage? 0.19 * 155 (using total number of IP interviewed)

 

I DOUBT if your estimation is accurate......

Little hostile there, drken. If you don't like my 'estimation', I guess just don't use the info?

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I think it was a correct estimate- if you beat the 19 percentile you've ranked above 19% of the total - I don't believe you need standard deviate or the distribution to know what number is a percentile- but I could be wrong!

Probably right. Thanks

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How did you come up with 125?

How can you estimate this without having the interview score distribution, mean or SD ?

 

Or did you just take the percentage? 0.19 * 155 (using total number of IP interviewed)

 

I DOUBT if your estimation is accurate......

 

According to the post-interview email that was sent yesterday from Dr. Ziola, there was a total of 155 IP-pool applicants interviewed. Of those 155 total, the bottom 19%, equating to 29.45 is dropped (feel free to do that calculation if you have concerns). This means that there are approximately 125 IP-pool applicants left for the minimum estimated 75 available seats. None of itsalwayssunny's numbers are an estimation.

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OK let's have some fun with stats!

 

Z score, the relationship of a score to its mean, is defined as

Z= (your score - mean) / standard deviation of population

 

Meaning that a z score of 0 means that your values is the mean and a positive v score is above the mean. It is very useful in comparison of data from different sets. It contains all necessary info about the mean and standards deviation.

 

So our z score cutoff limit of +0.19 is slightly greater than 0. This implies that the cutoff was set right above the mean score of the population or 0.5753. Meaning 57% of people failed the interview.

 

Our population size is 155 each only contributing one data point. The z score with a normal distribution gives us a probabilities that only 66/155 exceeded a z score of 19%. 66 people passing this is too small a number considering everything Dr. Z said.

 

What's more likely is that they gave us 19% as a percentile of the population. Giving us a number of 125/155 passing.

 

The reality is sit tight and do what you need to do until the phone rings or they send an owl or whatever....

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Thanks for the info! 

 

 

Are you IP as well?

 

Do they keep contacting references up until the 13th? Or do they finish it much earlier? 

 

Yes I am In-province. From what i know, they finish earlier. Last year they contacted 2 references for everyone, and all 3 for 8 candidates. I am guessing this because they need to rank everyone , as well as screen certain applicants individually, so i think they would try to finish references asap so they have time for that.  

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I wonder why three references are contacted only for a few.

 

 

Im pretty sure it's because either one of their references said something negative (which did happen last year to someone I know) or two applicants were tied in the overall ranking so they use the references and full file review to decide order.

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